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A solid $A B$ has the NaCl structure. If radius of cation $A^{+}$is 120 pm , the maximum possible value of the radius of the anion $B^{-}$is
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Verified Answer
The correct answer is:
290 pm
For NaCl crystal,
Radius of cation/radius of anion $=0.414$
$\begin{aligned}
& \frac{r_{A^{+}}}{r_{B^{-}}}=0.414 \\
& r_{B^{-}}=\frac{r_{A^{+}}}{0.414}=\frac{120}{0.414} \\
& =290 \mathrm{pm} \\
&
\end{aligned}$
Radius of cation/radius of anion $=0.414$
$\begin{aligned}
& \frac{r_{A^{+}}}{r_{B^{-}}}=0.414 \\
& r_{B^{-}}=\frac{r_{A^{+}}}{0.414}=\frac{120}{0.414} \\
& =290 \mathrm{pm} \\
&
\end{aligned}$
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