Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A solid body of constant heat capacity $1 \mathrm{~J} /{ }^{\circ} \mathrm{C}$ is being heated by keeping it in contact with reservoirs in two ways:
(i) Sequentially keeping in contact with 2 reservoirs such that each reservoir supplies same amount of heat.
(ii) Sequentially keeping in contact with 8 reservoirs such that each reservoir supplies same amount of heat.
In both the cases body is brought from initial temperature $100^{\circ} \mathrm{C}$ to final temperature $200^{\circ} \mathrm{C}$. Entropy change of the body in the two cases respectively is:
PhysicsThermodynamicsJEE Main
Options:
  • A $\ln 2,2 \ln 2$
  • B $2 \ln 2,8 \ln 2$
  • C $\ln 2,4 \ln 2$
  • D $\ln 2, \ln 2$
Solution:
2955 Upvotes Verified Answer
The correct answer is: $\ln 2, \ln 2$
The entropy change of the body in the two cases is same as entropy is a state function.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.