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Question: Answered & Verified by Expert
A solid cylinder is made of radius R and height 3R having mass density ρ . Now two half spheres of radius R are removed from both ends. The moment of inertia of remaining portion about axis ZZ' can be calculated as 296KπR5ρ . Find K.

PhysicsRotational MotionJEE Main
Solution:
2938 Upvotes Verified Answer
The correct answer is: 5
  Mcylinder=πR2×3Rρ.lcylinder=123πR3ρR2

Msphere=23πR3ρ,lsphere=2523πR3ρR2

  lremaining=lcylinder-lsphere=2930πR5ρ.

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