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Question: Answered & Verified by Expert
A solid sphere of lithium is rotating with angular frequency ' $\omega$ ' about an axis passing through its diameter. If its temperature is raised by $50^{\circ} \mathrm{C}$ then its new angular frequency is $\left(\alpha_{\text {lithium }}=60 \times 10^{-5}{ }^{\circ} \mathrm{C}^{-1}\right)$
PhysicsRotational MotionAP EAMCETAP EAMCET 2018 (24 Apr Shift 2)
Options:
  • A $0.99 \omega$
  • B $0.73 \omega$
  • C $0.83 \omega$
  • D $0.94 \omega$
Solution:
1470 Upvotes Verified Answer
The correct answer is: $0.94 \omega$
No solution. Refer to answer key.

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