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Question: Answered & Verified by Expert
A solid sphere of radius R has a charge Q distributed in its volume with a charge density ρ=kra, where k and a are constants and r is the distance from its centre. If the electric field at r=R2 is 18 times that at r=R, then find the value of a
PhysicsElectrostaticsJEE Main
Options:
  • A 2
  • B 3
  • C 2.5
  • D 0.2
Solution:
1871 Upvotes Verified Answer
The correct answer is: 2
From Gauss' theorem,

Eqr2          q=charge enclosed

E2E1=q2q1=r12r22

8=0R4πr2kradr0R/24πr2kradr×R22R2

Solving this equation we get, a=2.

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