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A solid sphere of uniform density and radius applies a gravitational force of attraction equal to on a particle placed at a distance from the centre of the sphere. A spherical cavity of the radius is now made in the sphere as shown in the figure. The sphere with the cavity now applies a gravitational force on the same particle. The ratio is

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The correct answer is:
From the superposition principle,
Here, Fr = force due to remaining part = F2
and Fc = force due to cavity
Now,
Here, Fr = force due to remaining part = F2
and Fc = force due to cavity
Now,
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