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Question: Answered & Verified by Expert
A solution at 20oC is composed of 1.5 mol of benzene and 3.5 mol of toluene. If the vapour pressure of pure benzene and pure toluene at this temperature are 74.7 torr and 22.3 torr respectively, then the total vapour pressure of the solution and the benzene mole fraction in equilibrium with it will be, respectively:
ChemistrySolutionsJEE MainJEE Main 2015 (10 Apr Online)
Options:
  • A 30.5 torr and 0.389
  • B 35.0 torr and 0.480
  • C 38.0 torr and 0.589
  • D 35.8 torr and 0.280
Solution:
2540 Upvotes Verified Answer
The correct answer is: 38.0 torr and 0.589

XBenzene =1.55=0.3

XToluene=3.55=0.7
According to Raoult's Law

P=xAP°A +xBP°B

Ptotal=0.3×74.7+0.7×22.3

=22.41+15.61=38.02

38 Torr

By Dalton's law to vapour phase

Mole fraction of a gas in a mixture of gas = Partial pressure of gas P 1 Total no.moles in the mixture

XBenzeneVapour phase=0.3×74.738=22.4138

=0.589

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