Search any question & find its solution
Question:
Answered & Verified by Expert
A solution contains $1.2046 \times 10^{24}$ hydrochloric acid molecules in one $\mathrm{dm}^{3}$ of the solution. The strength of the solution is
Options:
Solution:
1999 Upvotes
Verified Answer
The correct answer is:
$2 \mathrm{~N}$
Moles of $\mathrm{HCl}=\frac{1.2046 \times 10^{24}}{6.023 \times 10^{23}}=2$
$\begin{aligned}
\therefore \text { Normality } &=\frac{\text { moles of IICl }}{\text { volume of solution }\left(\mathrm{L} \text { or } \mathrm{dm}^{3}\right)} \\
&=\frac{2}{1}=2 \mathrm{~N}
\end{aligned}$
$\begin{aligned}
\therefore \text { Normality } &=\frac{\text { moles of IICl }}{\text { volume of solution }\left(\mathrm{L} \text { or } \mathrm{dm}^{3}\right)} \\
&=\frac{2}{1}=2 \mathrm{~N}
\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.