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A solution is $0 \cdot 25 \%$ by mass. What is the weight of solvent containing $1.25 \mathrm{~g}$ solute?
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$498.758g$
Mass of solution $=100 \mathrm{~g}$. Mass of solute $=0.25 \mathrm{~g}$.
$\therefore$ Mass of solvent $=100-0.25=99.75 \mathrm{~g}$.
$0.25$ of solute is present in $99.75 \mathrm{~g}$ of solvent
$\therefore 1.25 \mathrm{~g} .$ of solute will be present in
$\frac{99.75 \times 1.25}{0.25}=498.75 \mathrm{~g}$ of solvent.
$\therefore$ Mass of solvent $=100-0.25=99.75 \mathrm{~g}$.
$0.25$ of solute is present in $99.75 \mathrm{~g}$ of solvent
$\therefore 1.25 \mathrm{~g} .$ of solute will be present in
$\frac{99.75 \times 1.25}{0.25}=498.75 \mathrm{~g}$ of solvent.
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