Search any question & find its solution
Question:
Answered & Verified by Expert
A solution is prepared by adding 1 mole ethyl alcohol in 9 mole water. The mass percent of solute in the solution is ________ (Integer answer) (Given : Molar mass in \(\mathrm{g} \mathrm{mol}^{-1}\) Ethyl alcohol : 46 water: 18)
Solution:
1440 Upvotes
Verified Answer
The correct answer is:
22
Mass percent of Alcohol
$\begin{aligned} & =\frac{\text { Mass of ethyl alcohol }}{\text { Total mass of solution }} \times 100 \\ & =\frac{1 \times 46}{1 \times 46+9 \times 18} \times 100=\frac{4600}{208} \\ & =22.11 \text { Or } 22\end{aligned}$
$\begin{aligned} & =\frac{\text { Mass of ethyl alcohol }}{\text { Total mass of solution }} \times 100 \\ & =\frac{1 \times 46}{1 \times 46+9 \times 18} \times 100=\frac{4600}{208} \\ & =22.11 \text { Or } 22\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.