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A solution of sulphur dioxide in water reacts with $\mathrm{H}_2 \mathrm{~S}$ precipitating sulphur. Here sulphur dioxide acts as
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An oxidising agent
$\underset{\text { reducing agent }}{2 \mathrm{H}_2 \mathrm{~S}}+\underset{\text { oxidising agent }}{\mathrm{SO}_2} \rightarrow 2 \mathrm{H}_2 \mathrm{O}+3 \mathrm{~S}$
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