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Question: Answered & Verified by Expert
A solution which is 10–3 M each in Mn2 + , Fe2 + , Zn2 + and Hg2 + is treated with 10 - 16 M sulphide ion. If Ksp of MnS, FeS, ZnS and HgS are 10 - 13 , 10–18 , 10–24 and 10–53 respectively, which one will precipitate first ?
ChemistryIonic EquilibriumNEET
Options:
  • A FeS
  • B MgS
  • C HgS
  • D ZnS
Solution:
1262 Upvotes Verified Answer
The correct answer is: HgS
[S2 - ] need for precipitation of

FeS = 1 0 - 1 8 1 0 - 3 = 1 0 - 1 5  M

MnS = 1 0 - 1 3 1 0 - 3 = 1 0 - 1 0  M

HgS = 1 0 - 5 3 1 0 - 3 = 1 0 - 5 M 

ZnS = 1 0 - 2 4 1 0 - 3 = 1 0 - 2 1 M

Thus  minimum [S2 - ] for precipitation is for HgS it will be precipitated first.

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