Search any question & find its solution
Question:
Answered & Verified by Expert
A sound wave of frequency $\mathrm{v} \mathrm{Hz}$ initially travels a distance of $1 \mathrm{~km}$ in air. Then, it gets reflected into a water reservoir of depth $600 \mathrm{~m}$. The frequency of the wave at the bottom of the reservoir is
$$
\text { ( } V_{\text {air }}=340 \mathrm{~m} / \mathrm{s} V_{\text {water }}=1484 \mathrm{~m} / \mathrm{s} \text { ) }
$$
Options:
$$
\text { ( } V_{\text {air }}=340 \mathrm{~m} / \mathrm{s} V_{\text {water }}=1484 \mathrm{~m} / \mathrm{s} \text { ) }
$$
Solution:
1981 Upvotes
Verified Answer
The correct answer is:
$v \mathrm{~Hz}$
The frequency of sound wave remains constant
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.