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Question: Answered & Verified by Expert

A source of sound having frequency 300 Hz and a receiver are located along the same line normal to the wall as shown in the figure. Both the source and the receiver are stationary and the wall recedes from the source with a velocity of 20 m s-1. If the beat frequency registered by the receiver is 240x Hz, then what is the value of x? [velocity of sound = 330 m s-1]

PhysicsWaves and SoundJEE Main
Solution:
1531 Upvotes Verified Answer
The correct answer is: 7
As ; f1=f (for direct sound)

Now for reflected sound f2=V-20V+20f

If b is the beat frequency,



b=f1-f2

f-V-20V+20f=f×40V+20

=300×40350=2407 Hz

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