A source supplies heat to a system at the rate of 1000 W . If the system performs work at a rate of 200 W . The rate at which internal energy of the system increases is

Question

A source supplies heat to a system at the rate of 1000 W . If the system performs work at a rate of 200 W . The rate at which internal energy of the system increases is, 600 W, 800 W, 500 W, 1200 W

MARKS App · Accepted Answer

According to the first law of thermodynamics, Q = W + U . Upon differentiation, we get d Q d t = d W d t + d U d t ⇒ d U d t = d Q d t - d W d t Given: d Q d t = 1000 W d W d t = 200 W Therefore, d U d t = 1000 W - 200 W = 800 W

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