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A sphere is suspended by a thread of length $l$ What minimum horizontal velocity has to be imparted the ball for it to reach the height of the suspension?
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2950 Upvotes
Verified Answer
The correct answer is:
$\sqrt{g l}$
KE given to a sphere at lowest point
= potential energy at the height of suspension $\frac{1}{2} m v^{2}=m g l$
$\therefore$
$$
v=\sqrt{2 g l}
$$
= potential energy at the height of suspension $\frac{1}{2} m v^{2}=m g l$
$\therefore$
$$
v=\sqrt{2 g l}
$$
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