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A sphere of mass $10 \mathrm{~kg}$ and radius $0.5 \mathrm{~m}$ rotates about a tangent. The moment of inertia of the sphere is
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$3.5 \mathrm{~kg} \mathrm{~m}^2$
M.I. about tangent $=I+M R^2$
$\begin{aligned} & =\frac{2}{5} M R^2+M R^2=\frac{7}{5} M R^2 \\ & =\frac{7}{5} \times(10) \times(0.5)^2=3.5 \mathrm{~kg} \mathrm{~m}^2\end{aligned}$
$\begin{aligned} & =\frac{2}{5} M R^2+M R^2=\frac{7}{5} M R^2 \\ & =\frac{7}{5} \times(10) \times(0.5)^2=3.5 \mathrm{~kg} \mathrm{~m}^2\end{aligned}$
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