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Question: Answered & Verified by Expert
A sphere rolls down on an inclined plane of inclination $\theta$. What is the acceleration as the sphere reaches the bottom?
PhysicsRotational MotionVITEEEVITEEE 2021
Options:
  • A $\frac{5}{7} g \sin \theta$
  • B $\frac{3}{5} g \sin \theta$
  • C $\frac{2}{7} g \sin \theta$
  • D $\frac{2}{5} g \sin \theta$
Solution:
2255 Upvotes Verified Answer
The correct answer is: $\frac{5}{7} g \sin \theta$
$a=\frac{g \sin \theta}{1+\frac{K^2}{R^2}}=\frac{g \sin \theta}{1+\frac{2}{5}}=\frac{5}{7} g \sin \theta$

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