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A spherical ball $A$ of mass 4 kg, moving along a straight line strikes another spherical ball $B$ of mass $1 \mathrm{kg}$ at rest. After the collision, $A$ and $B$ move with velocities $y_{1} \mathrm{ms}^{-1}$ and $v_{2} \mathrm{ms}^{-1}$ respectively making angles of $30^{\circ}$ and $60^{\circ}$ with
respect to the original direction of motion of $A .$ The ratio $\frac{y_{1}}{v_{2}}$ will be
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respect to the original direction of motion of $A .$ The ratio $\frac{y_{1}}{v_{2}}$ will be
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Verified Answer
The correct answer is:
$\frac{\sqrt{3}}{4}$
Along $y$ -axis momentum remains zero. Here
$$
\begin{aligned}
4 v_{1} \sin 30^{\circ} &=v_{2} \sin 60^{\circ} \\
\frac{y_{1}}{v_{2}} &=\frac{\sqrt{3}}{4}
\end{aligned}
$$
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