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Question: Answered & Verified by Expert
A spherical ball is kept at the corner of a rectangular room such that the ball touches two (Perpendicular) walls and lies on the floor. If a point on the sphere is at distances of $9,16,25$ from the two walls and the floor, then a possible radius of the sphere is
MathematicsCircleKVPYKVPY 2017 (19 Nov SB/SX)
Options:
  • A 13
  • B 15
  • C 26
  • D 36
Solution:
1420 Upvotes Verified Answer
The correct answer is: 13


$(r-9)^{2}+(r-16)^{2}+(r-25)^{2}=r^{2}$
solving this
$\begin{array}{l}
2 r^{2}-100 r+962=0 \\
r^{2}-50 r+481=0 \\
r=37, r=13
\end{array}$
possible radius $=13$
According to option

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