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A spherical marble of radius $1 \mathrm{~cm}$ is stuck in a circular hole of radius slightly smaller than its own radius (for calculation purpose, both can be taken same) at the bottom of a bucket of height $40 \mathrm{~cm}$ and filled with water up to $10 \mathrm{~cm}$. If the mass of the marble is $20 \mathrm{~g}$, the net force on the marble due to water is close to
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$0.04 \mathrm{~N}$ dowrward
$=(\rho g h) A-\left(\frac{2}{3} \pi R^{3}\right) \rho g$ $=A\left(10^{3} \times 10 \times 10 \times 10^{-2}\right)-\frac{2}{3} \pi \times 10^{-2} \times 10^{3} \times 10$ Area $=0.04 \mathrm{~N}$ dowanward
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