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Question: Answered & Verified by Expert
A spring is compressed between two blocks of masses $m_1$ and $m_2$ placed on a horizontal frictionless surface as shown in the figure. When the blocks are released, they have initial velocity of $v_1$ and $v_2$ as shown. The blocks travel distances $x_1$ and $x_2$ respectively before coming to rest. The ratio $\left(\frac{x_1}{x_2}\right)$ is

PhysicsCenter of Mass Momentum and CollisionJEE MainJEE Main 2012 (12 May Online)
Options:
  • A
    $\frac{m_2}{m_1}$
  • B
    $\frac{m_1}{m_2}$
  • C
    $\sqrt{\frac{m_2}{m_1}}$
  • D
    $\sqrt{\frac{m_1}{m_2}}$
Solution:
1026 Upvotes Verified Answer
The correct answer is:
$\frac{m_2}{m_1}$
No Solution Available

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