A spring of force constant 800 N m - 1 has an extension of 5 cm . The work done in extending it from 5 cm to 15 cm is

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Question: Answered & Verified by Expert

A spring of force constant

800 N m^{- 1}

has an extension of

5 cm

. The work done in extending it from

5 cm

to

15 cm

is

PhysicsWork Power EnergyNEET

Options:

A $16 J$
B $8 J$
C $32 J$
D $24 J$

Solution:

1330 Upvotes Verified Answer

The correct answer is:

8 J

W = \frac{1}{2} k (x_{2}^{2} - x_{1}^{2})

W = \frac{1}{2} \times 800 [{(15 \times 1 0^{- 2})}^{2} - {(5 \times 1 0^{- 2})}^{2}]

W = 400 \times 200 \times 10^{- 4} = 8 J

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