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A spring of force constant $800 \mathrm{~N} / \mathrm{m}$ has an extension of $5 \mathrm{~cm}$. The work done is extending it from $5 \mathrm{~cm}$ to $15 \mathrm{~cm}$ is
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$8 \mathrm{~J}$
$8 \mathrm{~J}$
$\mathrm{W}=\int_{x_1}^{x_2} F d x=\int_{x_1}^{x_2} K x d x=K\left[\frac{x^2}{2}\right]_{x_1}^{x_2}=\frac{K}{2}\left[x_2^2-x_1^2\right]=\frac{800}{2}\left[(0.15)^2-(0.05)^2\right]=8 \mathrm{~J}$
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