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Question: Answered & Verified by Expert
A square loop, carrying a steady current $I$, is placed in a horizontal plane near a long straight conductor carrying a steady current $I_1$ at a distance $d$ from the conductor as shown in figure. The loop will experience

PhysicsMagnetic Effects of CurrentNEETNEET 2011 (Mains)
Options:
  • A a net repulsive force away from the conductor
  • B a net torque acting upward perpendicular to the horizontal plane
  • C a net torque acting downward normal to the horizontal plane
  • D a net attractive force towards the conductor
Solution:
1491 Upvotes Verified Answer
The correct answer is: a net attractive force towards the conductor


$$
\begin{aligned}
& \mathbf{F}_2=-\mathbf{F}_4 \\
& \mathbf{F}_1=\frac{\mu_0 I_1 I l}{2 \pi d} \\
& \mathbf{F}_2=\frac{\mu_0 I_1 I l}{2 \pi(d+l)} \\
& \mathbf{F}_1>\mathbf{F}_3 \\
& F_{\text {net }}=F_1-F_3
\end{aligned}
$$
So, wire atrract loop.

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