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A square loop, carrying a steady current $\mathrm{I}$, is placed in horizontal plane near a long straight conductor carrying a steady current $I_{1}$ at a distance of $\mathrm{d}$ from the conductor as shown in figure. The loop will experience
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Verified Answer
The correct answer is:
a net attractive force towards the conductor
$$
\begin{array}{l}
\mathrm{F}_{2}=-\mathrm{F}_{4} \\
\mathrm{~F}_{1}=\frac{\mu_{0} \mathrm{I}_{1} \mathrm{I} l}{2 \pi \mathrm{d} l} \\
\mathrm{~F}_{2}=\frac{\mu_{0} \mathrm{I}_{1} \mathrm{I}}{2 \pi(\mathrm{d}+\mathrm{l})} \\
\mathrm{F}_{1}>\mathrm{F}_{3} \\
\mathrm{~F}_{\text {net }}=\mathrm{F}_{1}-\mathrm{F}_{3}
\end{array}
$$
So, wire attract loop.
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