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A square loop of side ' $a$ ' and carrying a current ' $\mathrm{T}$ ' is suspended from an insulting hanger of a spring balance as shown in the figure. The transverse magnetic field ' $\mathrm{B}$ ' directed into the paper occurs only at the bottom side of the loop. When direction of current in the loop is reversed, the change in the reading of spring balance is
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The correct answer is:
$2 \mathrm{IaB}$
When direction of current in the loop is reversed, the change in the reading of spring balance
$=2 \mathrm{Ia} \mathrm{B}$
$=2 \mathrm{Ia} \mathrm{B}$
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