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Question: Answered & Verified by Expert
A standing wave propagating with velocity 300 m s-1 in an open pipe of length 4 m has four nodes. The frequency of the wave is
PhysicsWaves and SoundNEET
Options:
  • A 75 Hz
  • B 100 Hz
  • C 150 Hz
  • D 300 Hz
Solution:
2289 Upvotes Verified Answer
The correct answer is: 150 Hz


Nodes are produced in the open pipe as shown in figure.

So, 2λ=4

λ=42=2 m

From the wave equation,

v=nλ

n=vλ

=3002

=150 Hz

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