Search any question & find its solution
Question:
Answered & Verified by Expert
A stationary hydrogen atom undergoes a transition from $n=5$ to $n=4$. Recoil speed of the atom is $(R=$ Rydberg constant, $h=$ Planck's constant and $m=$ mass of the proton).
Options:
Solution:
1542 Upvotes
Verified Answer
The correct answer is:
$\frac{9 R h}{400 m}$
For transition $5 \rightarrow 4$,
Momentum of photon, $p=\frac{h}{\lambda}=h R\left(\frac{1}{16}-\frac{1}{25}\right)$ and recoil speed, $v=\frac{p}{m}=\frac{h R\left(\frac{1}{16}-\frac{1}{25}\right)}{m}=\frac{9 h R}{400 m}$
Momentum of photon, $p=\frac{h}{\lambda}=h R\left(\frac{1}{16}-\frac{1}{25}\right)$ and recoil speed, $v=\frac{p}{m}=\frac{h R\left(\frac{1}{16}-\frac{1}{25}\right)}{m}=\frac{9 h R}{400 m}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.