A steel scale is to be prepared such that the millimeter intervals are to be accurate within 6 × 10 - 5 mm . The maximum temperature variation from the temperature of calibration during the reading of the millimeter marks is (linear coefficient of expansion for steel is given as α = 12 × 10 - 6 ° C - 1 )

Question

A steel scale is to be prepared such that the millimeter intervals are to be accurate within 6 × 10 - 5 mm . The maximum temperature variation from the temperature of calibration during the reading of the millimeter marks is (linear coefficient of expansion for steel is given as α = 12 × 10 - 6 ° C - 1 ), 4 . 0 ° C, 4 . 5 ° C, 5 . 0 ° C, 5 . 5 ° C

MARKS App · Accepted Answer

We know that thermal extension is given by, ∆ l = l 0 α ∆ T 6 × 10 - 5 = 1 × 12 × 10 - 6 × Δ ⊤ = 6 × 10 - 5 12 × 10 - 6 Δ T = 5 ° C

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