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A steel wire having a radius of $2.0 \mathrm{~mm}$, carrying a load of $4 \mathrm{~kg}$, is hanging from a ceiling. Given that $\mathrm{g}=3.1 \mathrm{~mm} / \mathrm{s}^2$, what will be the tensile stress that would be developed in the wire?
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The correct answer is:
$3.1 \times 10^6 \mathrm{~N} / \mathrm{m}^2$
Tensile stress = Force/Area
Tensile stress $=(4)(3.1 \pi) / \pi\left(2 \times 10^{-3}\right)^2$
Tensile stress $=3.1 \times 10^6 \mathrm{Nm}^{-2}$
Tensile stress $=(4)(3.1 \pi) / \pi\left(2 \times 10^{-3}\right)^2$
Tensile stress $=3.1 \times 10^6 \mathrm{Nm}^{-2}$
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