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A steel wire of 1 m long and $1 \mathrm{~mm}^2$ cross section area is hanged from rigid end when weight of 1 kg is hanged from it, then change in length will be
(Young's coefficient for wire $Y=2 \times 10^{11} \mathrm{~N} / \mathrm{m}^2$)
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(Young's coefficient for wire $Y=2 \times 10^{11} \mathrm{~N} / \mathrm{m}^2$)
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Verified Answer
The correct answer is:
$0.05$ mm
Young's coefficient of elasticity
$Y=\frac{m g L}{\pi r^2 \Delta L}$
Substituting the values, we get
$\Delta L=0.05 \mathrm{~mm}$
$Y=\frac{m g L}{\pi r^2 \Delta L}$
Substituting the values, we get
$\Delta L=0.05 \mathrm{~mm}$
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