Search any question & find its solution
Question:
Answered & Verified by Expert
A steel wire of length $1 \mathrm{~m}$, mass $0.1 \mathrm{~kg}$ and uniform area of cross section $10^{-6} \mathrm{~m}^2$ is rigidly fixed at both the ends without any tension. Its temperature is lowered by $20^{\circ} \mathrm{C}$ and transverse waves are set up by plucking the wire at the middle. The frequency of the fundamental mode is
$$
\left(\mathrm{Y}=200 \mathrm{GPa}, \alpha=1.21 \times 10^{-5}{ }^{\circ} \mathrm{C}^{-1}\right)
$$
Options:
$$
\left(\mathrm{Y}=200 \mathrm{GPa}, \alpha=1.21 \times 10^{-5}{ }^{\circ} \mathrm{C}^{-1}\right)
$$
Solution:
2864 Upvotes
Verified Answer
The correct answer is:
$11 \mathrm{~Hz}$
No solution. Refer to answer key.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.