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Question: Answered & Verified by Expert
A steel wire, of uniform area 2 m2, is heated up to 50°C and is stretched by tying its ends rigidly. The change in tension, when the temperature falls from 50 °C to 30 °C is (Take Y=2×1011 N m-2, α=1.1 ×10-5 °C-1)
PhysicsThermal Properties of MatterNEET
Options:
  • A 1.5 ×1010 N
  • B 5 N
  • C 88 N
  • D 2.5×1010 N
Solution:
1089 Upvotes Verified Answer
The correct answer is: 88 N

L= αLT=FALY

 F= αTAY

=1.1×10-5×50-30×2×10-6×2×1011

=88 N

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