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A step down transformer has \( 50 \) turns on secondary and \( 1000 \) turns on primary winding. If a
transformer is connected to \( 220 \mathrm{~V} 1 \mathrm{AA} \).C. source, what is output current of the transformer?
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transformer is connected to \( 220 \mathrm{~V} 1 \mathrm{AA} \).C. source, what is output current of the transformer?
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Verified Answer
The correct answer is:
\( 20 \mathrm{~A} \)
Given, number of turns on secondary, $N_{s}=50 ;$ number of turns on primary, $N_{P}=1000 ;$ source voltage $=220 \mathrm{~V} ;$
current $=1 \mathrm{~A}$.
We know $\frac{N_{s}}{N_{p}}=\frac{V_{s}}{V_{p}}=\frac{I_{p}}{I_{s}}$
Therefore $\frac{N_{s}}{N_{p}}=\frac{I_{p}}{I_{s}} \Rightarrow I_{s}=\frac{N_{p}}{N_{s}} I_{p}$
Substituting the values, we get
$I_{s}=\frac{1000}{50} \times 1=20 \mathrm{~A}$
Thus, output current of transformer $=20 \mathrm{~A}$
current $=1 \mathrm{~A}$.
We know $\frac{N_{s}}{N_{p}}=\frac{V_{s}}{V_{p}}=\frac{I_{p}}{I_{s}}$
Therefore $\frac{N_{s}}{N_{p}}=\frac{I_{p}}{I_{s}} \Rightarrow I_{s}=\frac{N_{p}}{N_{s}} I_{p}$
Substituting the values, we get
$I_{s}=\frac{1000}{50} \times 1=20 \mathrm{~A}$
Thus, output current of transformer $=20 \mathrm{~A}$
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