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A stone dropped from the top of the tower reaches ground in $4 \mathrm{~s}$. Height of the tower is $\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)$
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The correct answer is:
$80 \mathrm{~m}$
Given, $t=4 \mathrm{~s}, u=0, g=10 \mathrm{~ms}^{-2}$
Using equation of motion,
$h=u t+\frac{1}{2} g t^{2}=\frac{1}{2} g t^{2}=\frac{1}{2} \times 10 \times(4)^{2}=80 \mathrm{~m}$
Using equation of motion,
$h=u t+\frac{1}{2} g t^{2}=\frac{1}{2} g t^{2}=\frac{1}{2} \times 10 \times(4)^{2}=80 \mathrm{~m}$
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