A stone is dropped from a height of 45 m on a horizontal level ground. There is horizontal wind blowing due to which horizontal acceleration of the stone becomes 10 m/s 2 . (Take g = 10 m/s 2 ). The time taken t by stone to reach the ground and the net horizontal displacement x of the stone from the time it is dropped and till it reaches the ground are respectively

Question

A stone is dropped from a height of 45 m on a horizontal level ground. There is horizontal wind blowing due to which horizontal acceleration of the stone becomes 10 m/s 2 . (Take g = 10 m/s 2 ). The time taken t by stone to reach the ground and the net horizontal displacement x of the stone from the time it is dropped and till it reaches the ground are respectively, t = 3 s, x = 45 m, t = 4 s, x = 54 m, t = 3 s, x = 54 m, t = 4 s, x = 45 m

MARKS App · Accepted Answer

Taking motion in vertical direction, u = 0 , g = 10 m/s 2 , h = 45 m h = u t + 1 2 g t 2 ⇒ h = 0 + 1 2 gt 2 ⇒ t = 2 h g = 2 × 4 5 1 0 ⇒ t = 3 sec. (b) Taking motion in horizontal direction, u = 0 , a = 10 m/s 2 , t = 3 sec x = ut + 1 2 at 2 ⇒ x = 0 + 1 2 1 0 3 2 ⇒ x = 45 m

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