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A stone is dropped from the top of a tower of height $\mathrm{h}=60 \mathrm{~m}$. Simultaneously another stone is projected vertically upwards from the foot of the tower. They meet at a height $\frac{2 \mathrm{~h}}{3}$ from the ground level. The initial velocity of the stone projected upwards is $\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)$.
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The correct answer is:
$30 \mathrm{~ms}^{-1}$
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