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Question: Answered & Verified by Expert
A stone of mass 1 kg is tied at one end of a string of length 1 m. It is whirled in a vertical circle at a constant speed of 4 m s-1. The tension in the string is 6 N when the stone is at (g=10 m s-2)
PhysicsLaws of MotionNEET
Options:
  • A Top of the circle
  • B Bottom of the circle
  • C Half way down
  • D None of these
Solution:
1587 Upvotes Verified Answer
The correct answer is: Top of the circle
When the string makes an angle θ with the vertical, then

T-mgcosθ=mv2r

Substituting the values, we obtain

6 - 1 1 0 cos θ = 4 2 . 1 1 = 16

cos θ = - 1

θ = 1 8 0 o

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