A stone of mass 20 g is projected from a rubber catapult of length 0 . 1 m and area of cross section 10 - 6 m 2 stretched by an amount 0 . 04 m . The velocity of the projected stone is m s - 1 . (Young's modulus of rubber = 0 . 5 × 10 9 N m - 2 )

Question

A stone of mass 20 g is projected from a rubber catapult of length 0 . 1 m and area of cross section 10 - 6 m 2 stretched by an amount 0 . 04 m . The velocity of the projected stone is m s - 1 . (Young's modulus of rubber = 0 . 5 × 10 9 N m - 2 ),

MARKS App · Accepted Answer

By energy conservation 1 2 · Y A L · x 2 = 1 2 m v 2 0 . 5 × 10 9 × 10 - 6 × ( 0 . 04 ) 2 0 . 1 = 20 1000 v 2 ∴ v 2 = 400 v = 20 m s - 1

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