A stone of mass 500 g is dropped from the top of a tower of 100 m height and simultaneously other stone of mass 1 kg is thrown horizontally with a speed of 10 m / s from same point. The height of the centre of mass of the above two stone system after 3 s is g = 10 m / s 2

Question

A stone of mass 500 g is dropped from the top of a tower of 100 m height and simultaneously other stone of mass 1 kg is thrown horizontally with a speed of 10 m / s from same point. The height of the centre of mass of the above two stone system after 3 s is g = 10 m / s 2, 45 m, 35 m, 55 m, none of these

MARKS App · Accepted Answer

If height of stones is h 1 and h 2 after t = 3 s then, h 1 = 100 - 1 2 gt 2 = 55 m h 2 = 100 - 1 2 gt 2 = 55 m h CM = m 1 h 1 + m 2 h 2 m 1 + m 2 = m ( 55 + 55 ) 2 m h CM = 55 m

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