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Question: Answered & Verified by Expert
A stone of mass 500 g is dropped from the top of a tower of 100 m height. Simultaneously another stone of mass 1 kg is thrown horizontally with a speed of 10 m s-1 from same point. The height of the centre of mass of the above two stone system after 3 sec is g=10 m s-2
PhysicsCenter of Mass Momentum and CollisionNEET
Options:
  • A 45 m
  • B 35 m
  • C 55 m
  • D none of these
Solution:
1167 Upvotes Verified Answer
The correct answer is: 55 m
If height of stones is h1 and h2 after t=3 sec then,

h1=100-12gt2=55 m

h2=100-12gt2=55 m

height of centre of mass of the two stone system,

hCM=m1h1+m2h2m1+m2=55 m

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