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A stone thrown upward with a speed $u$ from the top of the tower reaches
the ground with a velocity $3 u$. The height of the tower is
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the ground with a velocity $3 u$. The height of the tower is
Solution:
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Verified Answer
The correct answer is:
$4 u^2 / g$
$v^2=u^2+2 g h \Rightarrow(3 u)^2=(-u)^2+2 g h \Rightarrow h=\frac{4 u^2}{g}$
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