A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone?

Question

A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone?, π 2 ms − 2 and direction along the radius towards the centre, π 2 ms − 2 and direction along the radius away from the centre, π 2 ms − 2 and direction along the tangent to the circle, π 2 /4 ms − 2 and direction along the radius towards the centre

MARKS App · Accepted Answer

$a=\frac{v^2}{r}=\omega^2 r=4 \pi^2 n^2 r=4 \pi^2\left(\frac{22}{44}\right)^2 \times 1=\pi^2 \mathrm{~m} / \mathrm{s}^2$ and its direction is always along the radius and towards the centre.

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