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Question: Answered & Verified by Expert
A straight conductor of length 0.4 m is moving with a speed of 7 ms-1 perpendicular to the magnetic field of intensity of 0.9 Wb m-2. The induced emf across the conductor will be
PhysicsElectromagnetic InductionMHT CETMHT CET 2017
Options:
  • A 7.25 V
  • B 5.52 V
  • C 1.25 V
  • D 2.52 V
Solution:
2970 Upvotes Verified Answer
The correct answer is: 2.52 V
If a rod of length l is moved with velocity v at an angle θ to the length of the rod in a filed B which is perpendicular to the plane of motion, the flux linked with the area generated by the motion of rod in time t.
ϕ=Blv sinθt
So, e=dϕdt=Bv l sinθ
This will be maximum when

sinθ=max=1
i.e., the rod is moving perpendicular to its length and then
emax=Bvl
e=0.9×7×0.4=2.52 V

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