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A straight conductor of length $4 \mathrm{~m}$ moves at a speed of $10 \mathrm{~m} / \mathrm{s}$. When the conductor makes on angle of $30^{\circ}$ with the direction of magnetic field of induction of $0.1 \mathrm{~Wb}-\mathrm{m}^2$, then induced emf is
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The correct answer is:
$2 \mathrm{~V}$
Induced emf is given by
$\begin{aligned} e & =B v l \sin \theta \\ & =0.1 \times 10 < 4 \sin 30=2 \mathrm{~V}\end{aligned}$
$\begin{aligned} e & =B v l \sin \theta \\ & =0.1 \times 10 < 4 \sin 30=2 \mathrm{~V}\end{aligned}$
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