Search any question & find its solution
Question:
Answered & Verified by Expert
A straight line through the point $\mathrm{A}(3,4)$ is such that its intercept between the axes is bisected at A, its equation is
Options:
Solution:
1291 Upvotes
Verified Answer
The correct answer is:
$4 x+3 y=24$
A is mid point of line PQ.
$$
\therefore 3=\frac{\mathrm{a}+0}{2} \Rightarrow \mathrm{a}=6
$$
and $4=\frac{0+b}{2} \Rightarrow b=8$
Thus, equation of line is
$$
\begin{array}{l}
\frac{x}{6}+\frac{y}{8}=1 \\
\Rightarrow 4 x+3 y=24
\end{array}
$$
$$
\therefore 3=\frac{\mathrm{a}+0}{2} \Rightarrow \mathrm{a}=6
$$
and $4=\frac{0+b}{2} \Rightarrow b=8$
Thus, equation of line is
$$
\begin{array}{l}
\frac{x}{6}+\frac{y}{8}=1 \\
\Rightarrow 4 x+3 y=24
\end{array}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.