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A straight magnetic strip has a magnetic moment of $44 \mathrm{Am}^2$. If the strip is bent in a semicircular shape, its magnetic moment will be _______ $\mathrm{Am}^2$.
(given $\pi=\frac{22}{7}$ )
(given $\pi=\frac{22}{7}$ )
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The correct answer is:
28
Magnetic moment of straight wire $=\mathrm{mx} \ell=44$
Magnetic moment of arc
$\begin{aligned}& =\mathrm{m} \times 2 \mathrm{r} \\& =\mathrm{m} \times \frac{2 \ell}{\pi} \\& =\frac{44 \times 2}{\pi}=\frac{88}{\pi}=28\end{aligned}$
Magnetic moment of arc
$\begin{aligned}& =\mathrm{m} \times 2 \mathrm{r} \\& =\mathrm{m} \times \frac{2 \ell}{\pi} \\& =\frac{44 \times 2}{\pi}=\frac{88}{\pi}=28\end{aligned}$
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