Search any question & find its solution
Question:
Answered & Verified by Expert
A straight wire carrying a current $i_1$ amp runs along the axis of a circular current ${ }^{i_2}$ amp . Then the force of interaction between the two current carrying conductors is
Options:
Solution:
2994 Upvotes
Verified Answer
The correct answer is:
Zero
Direction of magnetic field due to circular current will be perpendicular to the plane of circle i.e. along the axis as shown in the diagram below.
Force due to magnetic field is given as
\(\mathrm{dF}=I(\overrightarrow{\mathrm{d}} \times \overrightarrow{\mathrm{B}})\)
Since both vector \(\overrightarrow{\mathrm{dl}}\) and \(\vec{B}\) are in same direction, the force of intercation between both the wires will be zero.
Force due to magnetic field is given as
\(\mathrm{dF}=I(\overrightarrow{\mathrm{d}} \times \overrightarrow{\mathrm{B}})\)
Since both vector \(\overrightarrow{\mathrm{dl}}\) and \(\vec{B}\) are in same direction, the force of intercation between both the wires will be zero.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.