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Question: Answered & Verified by Expert
A stream of water flowing horizontally with a speed of 15 $\mathrm{ms}^{-1}$ pushes out of tube of cross sectional area $10^{-2} \mathrm{~m}^2$ and hits at a vertical wall nearby. What is the force exerted on the wall by the impact of water, assuming it does not rebound?
PhysicsLaws of Motion
Solution:
2051 Upvotes Verified Answer
Given, speed of water $v=15 \mathrm{~ms}^{-1}$; Area of cross section, $a=10^{-2} \mathrm{~m}^2$ and
Volume of water coming out per second $=a \times v=10^{-2} \times 15$ $=0.15 \mathrm{~m}^2 \mathrm{~s}^{-1}$
$\therefore$ mass of the water hitting the wall per sec $=m$
$=$ volume $\times($ density of water $)=(0.15) \times\left(10^3\right)$ $=150 \mathrm{~kg}^{-1}$.
$\therefore$ force excreted on the wall $=m v / t=150 \times 15 / 1=2250 \mathrm{~N}$

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